j^2+11j+30=20

Solution for j^2+11j+30=20 equation:

Simplifying
j2 + 11j + 30 = 20

Reorder the terms:
30 + 11j + j2 = 20

Solving
30 + 11j + j2 = 20

Solving for variable 'j'.

Reorder the terms:
30 + -20 + 11j + j2 = 20 + -20

Combine like terms: 30 + -20 = 10
10 + 11j + j2 = 20 + -20

Combine like terms: 20 + -20 = 0
10 + 11j + j2 = 0

Factor a trinomial.
(10 + j)(1 + j) = 0

Subproblem 1
Set the factor '(10 + j)' equal to zero and attempt to solve:

Simplifying
10 + j = 0

Solving
10 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + j = 0 + -10

Combine like terms: 10 + -10 = 0
0 + j = 0 + -10
j = 0 + -10

Combine like terms: 0 + -10 = -10
j = -10

Simplifying
j = -10
Subproblem 2
Set the factor '(1 + j)' equal to zero and attempt to solve:

Simplifying
1 + j = 0

Solving
1 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + j = 0 + -1
j = 0 + -1

Combine like terms: 0 + -1 = -1
j = -1

Simplifying
j = -1
Solution
j = {-10, -1}